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What is a triangular section's moment of inertia around its base when the base is the axis of rotation?
43. What is a triangular section's moment of inertia around its base when the base is the axis of rotation?
- (1/12) * base * height^3
- (1/36) * base * height^3
- (1/48) * base * height^3
- (1/24) * base * height^3
Answer
The correct answer is: B) (1/36) * base * height^3
Explanation
This formula computes the moment of inertia of a triangular section toward its base when the base is the axis of rotation.