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C++ program to find the area of hexagon using class

Learn, how can we find the area of hexagon using the class and object approach?
Submitted by Shubh Pachori, on September 04, 2022

Example:

Input:
Enter Length of sides: 12.5

Output:
Area of Hexagon is 405.949

C++ code to find the area of hexagon using the class and object approach

#include <math.h>
#include <iostream>
using namespace std;

// create a class
class Hexagon {
  // private data members
 private:
  float length, area;

  // public member functions
 public:
  // putSides() function to insert 
  // length of sides
  void putSides() {
    cout << "Enter Length of sides: ";
    cin >> length;
  }

  // getArea() function to calculate 
  // the area of the hexagon
  double getArea() {
    // calculating area of the hexagon
    area = (6 * (length * length)) / (4.0 * tan((M_PI / 6)));

    // returning area
    return area;
  }
};

int main() {
  // create object
  Hexagon H;

  // float type variable to store area
  float area;

  // calling putSides() function to 
  // insert length of the side
  H.putSides();

  // calling getArea() function to calculate 
  // area of the Hexagon
  area = H.getArea();

  cout << "Area of Hexagon is " << area << endl;

  return 0;
}

Output:

Enter Length of sides: 23
Area of Hexagon is 1374.38

Explanation:

In the above code, we have created a class Hexagon, two float type data members length and area to store the length of sides and area of hexagon, and public member functions putSides() and getArea() to store the length of sides and to calculate the area of the hexagon.

In the main() function, we are creating an object H of class Hexagon, reading the inputted values by the user using putSides() function, and finally calling the getArea() member function to calculate the area of the hexagon. The getArea() function contains the logic to calculate the area of the hexagon and printing the result.

C++ Class and Object Programs (Set 2) »

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