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C program to print ODD numbers from 1 to N using while loop
This is an example of while loop - In this C program, we are going to learn how can we print all ODD numbers from given range (1 to N) using while loop?
Submitted by Manju Tomar, on March 10, 2018
Given a range (value of N) and we have to print all ODD numbers from 1 to N using while loop.
Example
Input:
Enter value of N: 10
Output:
ODD Numbers from 1 to 10:
1 3 5 7 9
Logic
- There are two variables declared in the program 1) number as a loop counter and 2) n to store the limit.
- Reading value of n by the user.
- Initialising loop counter (number) by 1 as initial value number =1
- Using while loop by checking the condition number<=n (value of number is less than or equal to n) - this will execute the loop until the value of number is less than or equal to n.
- Then, within the loop, we are checking the condition to check whether number is ODD or not, the condition is (number%2 != 0) - it returns true if number is not divisible by 2.
Program to print ODD numbers from 1 to N using while loop
#include <stdio.h>
int main() {
//loop counter declaration
int number;
//variable to store limit /N
int n;
//assign initial value
//from where we want to print the numbers
number = 1;
//input value of N
printf("Enter the value of N: ");
scanf("%d", & n);
//print statement
printf("Odd Numbers from 1 to %d:\n", n);
//while loop, that will print numbers
while (number <= n) {
//Here is the condition to check ODD number
if (number % 2 != 0)
printf("%d ", number);
// increasing loop counter by 1
number++;
}
return 0;
}
Output
Run(1)
Enter the value of N: 10
Odd Numbers from 1 to 10:
1 3 5 7 9
Run(2)
Enter the value of N: 100
Odd Numbers from 1 to 100:
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31
33 35 37 39 41 43 45 47 49 51 53 55 57 59
61 63 65 67 69 71 73 75 77 79 81 83 85 87
89 91 93 95 97 99
Another way to print ODD numbers from 1 to N
Since, we know that ODD numbers starts from 1 and ODD numbers are those numbers which are not divisible by 2. So, we can run a loop from 1 to N by increasing the value of loop counter by 2.
Consider the given code...
//initialising the number by 1
number = 1;
//print statement
printf("Odd Numbers from 1 to %d:\n", n);
//while loop, that will print numbers
while (number <= n) {
//print the number
printf("%d ", number);
//increase the value of number by 2
number += 2;
}
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