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Java program to check Neon number

In this java program, we are going to check whether a given number is Neon number or not? A number is a Neon number, if sum of the digits of square of a number is equal to the number itself. Submitted by IncludeHelp, on October 29, 2017

Given a number, and we have to check whether it is Neon number or not using Java program.

Neon Number

A number is a Neon number, if sum of the digits of square of a number is equal to the number itself.

Example:

Number 9 is a Neon number, because 9 is equal to sum of the digits of square of number (9x9 = 81 = 8+1 = 9).

Program to check Neon number in Java

import java.util.Scanner;

public class NeonNumber 
{
	public static void main(String[] args)
	{
		int n,square,sum=0;
		//create object of scanner.
		Scanner sc = new Scanner(System.in);

		//you have to enter number here.
		System.out.print("Enter the number: " );
		n=sc.nextInt();

		//calculate square.
		square=n*n;

		while(square>0)
		{
			sum=sum+square%10;
			square=square/10;
		}
		//condition for checking sum is equal or not.
		if(sum==n)
			System.out.println("Its a Neon number.");
		else
			System.out.println("Its not a Neon number.");
	}
}

Output

First run:
Enter the number: 9
Its a Neon number.

Second run:
Enter the number :6
Its not a Neon number.