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Golang program to trim specified characters from the left side of string using TrimLeft() function

Here, we are going to learn how to trim specified characters from the left side of string using TrimLeft() function in Golang (Go Language)?
Submitted by Nidhi, on March 17, 2021 [Last updated : March 03, 2023]

Trimming specified characters from the left side of string using TrimLeft() function in Golang

Problem Solution:

In this program, we will create a string and then trim specified characters from the left side of the specified string using TrimLeft() function and print the result on the console screen.

Program/Source Code:

The source code to trim specified characters from the left side of the string using the TrimLeft() function is given below. The given program is compiled and executed successfully.

Golang code to trim specified characters from the left side of string using TrimLeft() function

// Golang program to trim specified characters from
// the left side of string using TrimLeft() function

package main

import "fmt"
import "strings"

func main() {
	str := "!%Hello World!%"

	fmt.Printf("%s", strings.TrimLeft(str, "!%"))
}

Output:

Hello World!%

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In the main() function, we created a string variable str, which is initialized with "!%Hello World!%". After that, we trimmed "!" and "%" characters from the left side of the string using strings.TrimLeft() function and print result on the console screen.

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