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Golang program to demonstrate the switch case without optional statement and expression

Here, we are going to demonstrate the switch case without optional statement and expression in Golang (Go Language)?
Submitted by Nidhi, on February 20, 2021 [Last updated : March 02, 2023]

Switch case without optional statement and expression in Golang

Problem Solution:

In this program, we will demonstrate the switch case, here we will not use optional statements and expressions.

Program/Source Code:

The source code to demonstrate the switch case without an optional statement and expression is given below. The given program is compiled and executed successfully.

Golang code to demonstrate the example of switch case without optional statement and expression

// Golang program to demonstrate the switch case // without optional statement and expression. package main import "fmt" func main() { var month int=3 switch { case month==1: fmt.Println("JAN") case month==2: fmt.Println("FEB") case month==3: fmt.Println("MAR") case month==4: fmt.Println("APR") case month==5: fmt.Println("MAY") case month==6: fmt.Println("JUN") case month==7: fmt.Println("JUL") case month==8: fmt.Println("AUG") case month==9: fmt.Println("SEP") case month==10: fmt.Println("OCT") case month==11: fmt.Println("NOV") case month==12: fmt.Println("DEC") default: fmt.Println("Invalid Month") } }

Output:

MAR

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In the main() function, we demonstrated the use of a switch case without an optional statement and expression. Here, we used the "==" operator to select the correct case and executed the body for the same.

Golang Switch Statement Programs »



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