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VB.Net program to find the angle for specified sine value

By Nidhi Last Updated : November 14, 2024

Finding the angle for specified sine value

Here, we will find the angle for the specified sine value and print the angle values for different sine values.

VB.Net code to find the angle for specified sine value

The source code to find the angle for the specified sine value is given below. The given program is compiled and executed successfully.

'VB.Net program to find the angle for 
'specified sine value.

Module Module1

    Sub Main()
        Dim angle As Double= 0

        angle = Math.Asin(2)
        Console.WriteLine("Angle of specified sine value is: {0}", angle)

        angle = Math.Asin(0.3584)
        Console.WriteLine("Angle of specified sine value is: {0}", angle)

        angle = Math.Asin(0.0)
        Console.WriteLine("Angle of specified sine value is: {0}", angle)
    End Sub

End Module

Output:

Angle of specified sine value is: NaN
Angle of specified sine value is: 0.366553473829125
Angle of specified sine value is: 0
Press any key to continue . . .

Explanation:

In the above program, we created a module Module1 that contains the Main() method. In the Main() method we created a variable angle initialized with 0.

angle = Math.Asin(2)
Console.WriteLine("Angle of specified sine value is: {0}", angle)

angle = Math.Asin(0.3584)
Console.WriteLine("Angle of specified sine value is: {0}", angle)

angle = Math.Asin(0.0)
Console.WriteLine("Angle of specified sine value is: {0}", angle)

In the above code, we find the angle against the specified sine values and then printed them on the console screen.

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