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VB.Net find output programs (Data Types) | set 1

By Nidhi Last Updated : November 14, 2024

Question 1:

Module VBModule
    Sub Main()
        dim num1 as integer=10
        dim num2 as Double =10.24
        
        Console.WriteLine("Num1: "+num1)
        Console.WriteLine("Num2: "+num2)
    End Sub
End Module

Output:

Unhandled Exception:
System.InvalidCastException: Conversion from string "Num1: " to type 'Double' is not valid. ---> System.FormatException: Input string was not in a correct format.

Explanation:

The above program will generate an exception due to the below statements.

    Console.WriteLine("Num1: "+num1)
    Console.WriteLine("Num2: "+num2)

In Vb.net, we need to use the "&" operator for concatenation. The correct program is given below.

Module VBModule
    Sub Main()
        dim num1 as integer=10
        dim num2 as Double =10.24
        
        Console.WriteLine("Num1: "&num1)
        Console.WriteLine("Num2: "&num2)
    End Sub
End Module

Question 2:

Module VBModule
    Sub Main()
        dim num1 as integer=10
        dim num2 as Double =10.24
        
        Console.WriteLine("Num1: {0}",num1)
        Console.WriteLine("Num2: {1}",num2)
    End Sub
End Module

Output:

Num1: 10
Num2: 10.24

Explanation:

In the above program, we created 2 variables and printed them using Console.WriteLine() method.

Question 3:

Module VBModule
    Sub Main()
        dim num as integer=10
        dim length as integer=0
        
        length=sizeof(num)
        
        Console.WriteLine("Num: {0}",num)
        Console.WriteLine("Length: {0}",length)
    End Sub
End Module

Output:

error VBNC30451: 'sizeof' is not declared. It may be inaccessible due to its protection level.
There were 1 errors and 0 warnings.

Explanation:

The above program will generate a syntax error because the "sizeof" operator is not available in vb.net.

Question 4:

Module VBModule
    Sub Main()
        dim num1 as int=10
        dim num2 as Double =10.24
        
        Console.WriteLine("Num1: "&num1)
        Console.WriteLine("Num2: "&num2)
    End Sub
End Module

Output:

main.vb (4,24) : error VBNC30451: 'int' is not declared. It may be inaccessible due to its protection level.
There were 1 errors and 0 warnings.

Explanation:

The above program will generate a syntax error because int is not a built-in type in vb.net, we need to use integer. The correct program is given below,

Module VBModule
    Sub Main()
        dim num1 as integer=10
        dim num2 as Double =10.24
        
        Console.WriteLine("Num1: "&num1)
        Console.WriteLine("Num2: "&num2)
    End Sub
End Module

Question 5:

Module VBModule

    Sub Main()
        dim num1=10 as integer
        dim num2=10.24 as Double
        
        Console.WriteLine("Num1: {0}",num1)
        Console.WriteLine("Num2: {0}",num2)
    End Sub

End Module

Output:

main.vb (4,23) : error VBNC30205: End of statement expected.

main.vb (4,23) : error VBNC90019: Expected 'End'.

main.vb (5,26) : error VBNC90018: Expected end of line.

main.vb (7,16) : error VBNC90019: Expected 'End'.

main.vb (8,16) : error VBNC30203: Identifier expected.

main.vb (9,12) : error VBNC30203: Identifier expected.

main.vb (11,11) : error VBNC30203: Identifier expected.

There were 7 errors and 0 warnings.

Explanation:

The above program will generate syntax errors, because of the below declarative statements,

    dim num1=10 as integer
    dim num2=10.24 as Double

The correct program is given below,

Module VBModule
    Sub Main()
        dim num1 as integer=10
        dim num2 as Double=10.24
        
        Console.WriteLine("Num1: {0}",num1)
        Console.WriteLine("Num2: {0}",num2)
    End Sub
End Module