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Function overloading example based on Number of Arguments in C++

Learn: How to implement function overloading based on different number of argument in C++ programming language?

If you didn't read about the function overloading, I would recommend please read C++ function overloading before reading this article.

Function overloading based on Number of Arguments in C++

We can implement function overloading on the basis of number of arguments passed into function. Function overloading can be implementing in non-member function as well as member function of class.

Example 1

Example of non-member function based function overloading according to number of arguments is given below:

#include <iostream>
using namespace std;

void sum(int A, int B);
void sum(int A, int B, int C);
void sum(int A, int B, int C, int D);

int main()
{
    sum(1,2);
    sum(1,2,3);
    sum(1,2,3,4);
    
    return 0;
}

void sum(int A, int B)
{
     cout<< endl << "SUM is : "<< A+B;     
}

void sum(int A, int B, int C)
{
     cout<< endl << "SUM is : "<< A+B+C;     
}

void sum(int A, int B, int C, int D)
{
     cout<< endl << "SUM is : "<< A+B+C+D;     
}

Output

SUM is : 3
SUM is : 6
SUM is : 10

Example 2

Example of member function of class based function overloading according to number of arguments is given below:

#include <iostream>
using namespace std;

class funOver
{
      public:
        void sum(int A, int B);
        void sum(int A, int B, int C);
        void sum(int A, int B, int C, int D);
};

void funOver::sum(int A, int B)
{
     cout<< endl << "SUM is : "<< A+B;     
}

void funOver::sum(int A, int B, int C)
{
     cout<< endl << "SUM is : "<< A+B+C;     
}

void funOver::sum(int A, int B, int C, int D)
{
     cout<< endl << "SUM is : "<< A+B+C+D;     
}


int main()
{
    funOver ob;

    ob.sum(1,2);
    ob.sum(1,2,3);
    ob.sum(1,2,3,4);
            
    return 0;
}

Output

SUM is : 3
SUM is : 6
SUM is : 10