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Function overloading example based on Different types of Arguments in C++

Learn: How to implement function overloading based on Different types of arguments in C++ programming language?

If you didn't read about the function overloading, I would recommend please read C++ function overloading before reading this article.

Function overloading based on different types of arguments in C++

We can implement function overloading on the basis of different types of arguments pass into function. Function overloading can be implementing in non-member function as well as member function of class.

Example 1

Example of non-member function based function overloading according to different types of arguments is given below:

#include <iostream>
using namespace std;

void printVal(int   A);
void printVal(char  A);
void printVal(float A);

int main()
{
    printVal(10     );
    printVal('@'    );
    printVal(3.14f  );

    return 0;
}

void printVal(int   A)
{
     cout<< endl << "Value of A : "<< A;     
}

void printVal(char  A)
{
     cout<< endl << "Value of A : "<< A;     
}

void printVal(float A)
{
     cout<< endl << "Value of A : "<< A;     
}

Output

Value of A : 10
Value of A : @
Value of A : 3.14

Example 2

Example of member function of class based function overloading according to different types of arguments is given below:

#include <iostream>
using namespace std;

class funOver
{
      public:
        void printVal(int   A);
        void printVal(char  A);
        void printVal(float A);
};


void funOver::printVal(int   A)
{
     cout<< endl << "Value of A : "<< A;     
}

void funOver::printVal(char  A)
{
     cout<< endl << "Value of A : "<< A;     
}

void funOver::printVal(float A)
{
     cout<< endl << "Value of A : "<< A;     
}

int main()
{
    funOver ob;
   
    ob.printVal(10     );
    ob.printVal('@'    );
    ob.printVal(3.14f  );
    
    return 0;
}

Output

Value of A : 10
Value of A : @
Value of A : 3.14