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SHRT_MAX constant with example in C++
C++ SHRT_MAX constant: Here, we are going to learn about the SHRT_MAX macro constant of climits header in C++.
Submitted by IncludeHelp, on May 01, 2019
C++ SHRT_MAX macro constant
SHRT_MAX constant is a macro constant which is defied in climits header, it is used to get the maximum value of a short int object, it returns the maximum value that a short int object can store, which is 32767.
Note:
- The actual value depends on the compiler architecture or library implementation.
- We can also use <limits.h> header file instead of <climits> header as SHRT_MAX constant is defined in both of the libraries.
Syntax
Syntax of SHRT_MAX constant:
SHRT_MAX
Sample Input and Output
Constant call:
cout << SHRT_MAX;
Output:
32767
Example 1
C++ code to demonstrate example of SHRT_MAX constant with climits header:
// C++ code to demonstrate example of
// SHRT_MAX constant with climits header
#include<iostream>
#include<climits>
using namespace std;
int main()
{
//prinitng the value of SHRT_MAX
cout<<"SHRT_MAX: "<<SHRT_MAX<<endl;
return 0;
}
Output
SHRT_MAX: 32767
Example 2
C++ code to demonstrate example of SHRT_MAX constant with limits.h header file:
// C++ code to demonstrate example of
// SHRT_MAX constant with <limits.h> header file
#include<iostream>
#include<limits.h>
using namespace std;
int main()
{
//prinitng the value of SHRT_MAX
cout<<"SHRT_MAX: "<<SHRT_MAX<<endl;
return 0;
}
Output
SHRT_MAX: 32767