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SHRT_MAX constant with example in C++

C++ SHRT_MAX constant: Here, we are going to learn about the SHRT_MAX macro constant of climits header in C++.
Submitted by IncludeHelp, on May 01, 2019

C++ SHRT_MAX macro constant

SHRT_MAX constant is a macro constant which is defied in climits header, it is used to get the maximum value of a short int object, it returns the maximum value that a short int object can store, which is 32767.

Note:

  • The actual value depends on the compiler architecture or library implementation.
  • We can also use <limits.h> header file instead of <climits> header as SHRT_MAX constant is defined in both of the libraries.

Syntax

Syntax of SHRT_MAX constant:

SHRT_MAX

Sample Input and Output

Constant call:
cout << SHRT_MAX;

Output:
32767

Example 1

C++ code to demonstrate example of SHRT_MAX constant with climits header:

// C++ code to demonstrate example of 
// SHRT_MAX constant with climits header
#include<iostream>
#include<climits>
using namespace std;

int main()
{
   //prinitng the value of SHRT_MAX
    cout<<"SHRT_MAX: "<<SHRT_MAX<<endl;
    return 0;
}

Output

SHRT_MAX: 32767

Example 2

C++ code to demonstrate example of SHRT_MAX constant with limits.h header file:

// C++ code to demonstrate example of 
// SHRT_MAX constant with <limits.h> header file
#include<iostream>
#include<limits.h>
using namespace std;

int main()
{
   //prinitng the value of SHRT_MAX
    cout<<"SHRT_MAX: "<<SHRT_MAX<<endl;
    return 0;
}

Output

SHRT_MAX: 32767


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