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Linux shell script program to print program name using command line argument

By IncludeHelp Last updated : October 20, 2024

Problem statement

Here, we will create a shell script program to print program name using the $0 variable on the console screen.

Print program name using command line argument

The source code to create a Linux shell script program to print program name using command-line argument is given below. The given program is compiled and executed successfully on Ubuntu 20.04.

Linux shell script program to print program name using command line argument

#!/bin/bash
# Program name: "script_name.sh"
# shell script program to print program name using command line argument.
echo "Script program Name: $0"

Now, we will save the shell script program with the "script_name.sh" name.

Output

$ sh script_name.sh 
Script program Name: script_name.sh

Explanation

Here, we used the $0 variable to print the program name on the console screen.

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