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Kotlin program to find transpose of a matrix

Here, we are going to implement a Kotlin program to find the transpose matrix of a given matrix. Submitted by IncludeHelp, on May 08, 2020

Kotlin - Find transpose of a matrix

A transpose of a matrix is simply a flipped version of the original matrix.
We can transpose a matrix by switching its rows with its columns

Given a matrix, we have to find its transpose matrix.

Example

Input:
matrix:
[2, 3, 4, 5, 6]
[7, 8, 9, 0, 9]

Output:
Transpose Matrix :
[2, 7]
[3, 8]
[4, 9]
[5, 0]
[6, 9]

Program to find transpose of a matrix in Kotlin

package com.includehelp

import java.util.*

// Main function, Entry Point of Program
fun main(args: Array<String>) {

    //variable of rows and col
    val rows: Int
    val column: Int

    //Input Stream
    val scanner = Scanner(System.`in`)

    //Input no of rows and column
    print("Enter the number of rows and columns of matrix : ")
    rows   = scanner.nextInt()
    column = scanner.nextInt()

    //Create Array
    val matrixA     = Array(rows) { IntArray(column) }

    val transposeMatrix = Array(column) {IntArray(rows)}

    //Input Matrix
    println("Enter the Elements of First Matrix ($rows X $column} ): ")
    for(i in matrixA.indices){
        for(j in matrixA[i].indices){
            print("matrixA[$i][$j]: ")
            matrixA[i][j]=scanner.nextInt()
        }
    }

    //print Matrix A
    println("Matrix A : ")
    for(i in matrixA.indices){
        println("${matrixA[i].contentToString()} ")
    }

    //Transpose of Matrix
    for(i in transposeMatrix.indices){
        for(j in transposeMatrix[i].indices){
            transposeMatrix[i][j]=matrixA[j][i]
        }
    }

    //print Transpose Matrix
    println("Transpose Matrix : ")
    for(i in transposeMatrix.indices){
        println("${transposeMatrix[i].contentToString()} ")
    }
}

Output

Run 1:
Enter the number of rows and columns of matrix : 3
4
Enter the Elements of First Matrix (3 X 4} ):
matrixA[0][0]: 2
matrixA[0][1]: 3
matrixA[0][2]: 4
matrixA[0][3]: 5
matrixA[1][0]: 6
matrixA[1][1]: 7
matrixA[1][2]: 8
matrixA[1][3]: 9
matrixA[2][0]: 0
matrixA[2][1]: 1
matrixA[2][2]: 2
matrixA[2][3]: 3
Matrix A :
[2, 3, 4, 5]
[6, 7, 8, 9]
[0, 1, 2, 3]
Transpose Matrix :
[2, 6, 0]
[3, 7, 1]
[4, 8, 2]
[5, 9, 3]
----
Run 2:
Enter the number of rows and columns of matrix : 2
5
Enter the Elements of First Matrix (2 X 5} ):
matrixA[0][0]: 2
matrixA[0][1]: 3
matrixA[0][2]: 4
matrixA[0][3]: 5
matrixA[0][4]: 6
matrixA[1][0]: 7
matrixA[1][1]: 8
matrixA[1][2]: 9
matrixA[1][3]: 0
matrixA[1][4]: 9
Matrix A :
[2, 3, 4, 5, 6]
[7, 8, 9, 0, 9]
Transpose Matrix :
[2, 7]
[3, 8]
[4, 9]
[5, 0]
[6, 9]