Java - Integer Class lowestOneBit() Method

Integer class lowestOneBit() method: Here, we are going to learn about the lowestOneBit() method of Integer class with its syntax and example. By Preeti Jain Last updated : March 18, 2024

Integer class lowestOneBit() method

lowestOneBit() method is available in java.lang package.
lowestOneBit() method is used to find at most only single 1’s bit from the rightmost side one bit in the path of the lowest order of the given parameter [value] of integer type.
lowestOneBit() method is a static method, it is accessible with the class name too and if we try to access the method with the class object then also we will not get an error.
lowestOneBit() method does not throw an exception at the time of determining the lowest order bit in single digit.

Syntax

public static int lowestOneBit (int value);

Parameters

int value – represents the integer value to be parsed.

Return Value

The return type of this method is int, If the given argument is non-zero then, it returns at most only single 1’s bit in the path of rightmost side one bit of the given integer value. If the given argument is zero then, it returns the value 0.

Example

// Java program to demonstrate the example 
// of lowestOneBit (int value) method of Integer class

public class LowestOneBitOfIntegerClass {
    public static void main(String[] args) {
        int value = 1296;

        // It returns the string representation of the given unsigned 
        // integer value denoted by the argument in binary by calling
        // Integer.toBinaryString(value)
        System.out.println("Integer.toBinaryString(value): " + Integer.toBinaryString(value));

        // It returns the number with atmost 1's bits in the 
        // path of rightmost side one bit in the given argument 
        // 'value' by calling Integer.lowestOneBit(value)
        System.out.println("Integer.lowestOneBit(value): " + Integer.lowestOneBit(value));
    }
}

Output

Integer.toBinaryString(value): 10100010000
Integer.lowestOneBit(value): 16

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