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Java - Integer Class highestOneBit() Method
Integer class highestOneBit() method: Here, we are going to learn about the highestOneBit() method of Integer class with its syntax and example.
By Preeti Jain Last updated : March 18, 2024
Integer class highestOneBit() method
- highestOneBit() method is available in java.lang package.
- highestOneBit() method is used to find almost only single 1's bit from the leftmost side one bit in the path of the highest order of the given parameter [value] of integer type.
- highestOneBit() method is a static method, it is accessible with the class name too and if we try to access the method with the class object then also we will not get an error.
- highestOneBit() method does not throw an exception at the time of determining the highest order bit in single digit.
Syntax
public static int highestOneBit (int value);
Parameters
- int value – represents the integer value to be parsed.
Return Value
The return type of this method is int, If the given argument is non-zero then, it returns at most only single 1's bit in the path of leftmost side one bit of the given integer value. If the given argument is zero then, it returns the value 0.
Example
// Java program to demonstrate the example
// of highestOneBit (int value) method of Integer class
public class HighestOneBitOfIntegerClass {
public static void main(String[] args) {
int value = 1296;
// It returns the string representation of the given unsigned
// integer value denoted by the argument in binary by calling
// Integer.toBinaryString(value)
System.out.println("Integer.toBinaryString(value): " + Integer.toBinaryString(value));
// It returns the number with atmost 1's bits in the path of leftmost side
// one bit in the given argument 'value' by calling Integer.highestOneBit(value)
System.out.println("Integer.highestOneBit(value): " + Integer.highestOneBit(value));
}
}
Output
Integer.toBinaryString(value): 10100010000
Integer.highestOneBit(value): 1024