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C# - Join multiple data sources using LINQ
Learn, how to join multiple data sources using Linq in C#?
By Nidhi Last updated : April 01, 2023
Here, we will create three classes Employee, Department, and Address. Then we will join Employee and Department based on department id and join Employee with Address based on address id.
C# program to join multiple data sources using LINQ
The source code to join multiple data sources using Linq, which is given below. The given program is compiled and executed successfully on Microsoft Visual Studio.
// C# - Join multiple data sources using LINQ.
using System;
using System.Linq;
using System.Collections.Generic;
public class Employee {
public int ID;
public int Salary;
public int DEPT_ID;
public int ADD_ID;
public string Name;
}
public class Department {
public int DEPT_ID;
public string DEPT_Name;
}
public class Address {
public int ADD_ID;
public string address;
}
public class JoinDemo {
static void Main(string[] args) {
List <Employee> employees = new List <Employee> () {
new Employee {ID = 101, Name = "Amit ", Salary = 4000, DEPT_ID = 101, ADD_ID = 201},
new Employee {ID = 102, Name = "Amit ", Salary = 3800, DEPT_ID = 102, ADD_ID = 202},
new Employee {ID = 103, Name = "Salman", Salary = 3500, DEPT_ID = 103, ADD_ID = 203},
new Employee {ID = 104, Name = "Ram ", Salary = 2000, DEPT_ID = 101, ADD_ID = 204},
new Employee {ID = 105, Name = "Shyam ", Salary = 7000, DEPT_ID = 102, ADD_ID = 205},
new Employee {ID = 106, Name = "Kishor", Salary = 5000, DEPT_ID = 103, ADD_ID = 206}
};
List <Department> departments = new List <Department> () {
new Department {DEPT_ID = 101, DEPT_Name = "HR "},
new Department {DEPT_ID = 102, DEPT_Name = "ACCOUNTS "},
new Department {DEPT_ID = 103, DEPT_Name = "SALES "}
};
List <Address> addresses = new List <Address> () {
new Address {ADD_ID = 201, address = "AGRA "},
new Address {ADD_ID = 202, address = "BAMBAI "},
new Address {ADD_ID = 203, address = "CHENNAI "},
new Address {ADD_ID = 204, address = "DELHI "},
new Address {ADD_ID = 205, address = "GWALIOR "},
new Address {ADD_ID = 206, address = "JHASHI "}
};
var ResultQuery = (from emp in employees
join dept in departments on emp.DEPT_ID equals dept.DEPT_ID
join add in addresses on emp.ADD_ID equals add.ADD_ID
select new {
ID = emp.ID,
Name = emp.Name,
Salary = emp.Salary,
DeptName = dept.DEPT_Name,
address = add.address
}
).ToList();
Console.WriteLine("Employee Details: ");
foreach(var e in ResultQuery) {
Console.WriteLine("\tID: " + e.ID + ", Name: " + e.Name + ", Salary: " + e.Salary + ", Department: " + e.DeptName + ", Address: " + e.address);
}
}
}
Output
Employee Details:
ID: 101, Name: Amit , Salary: 4000, Department: HR , Address: AGRA
ID: 102, Name: Amit , Salary: 3800, Department: ACCOUNTS , Address: BAMBAI
ID: 103, Name: Salman, Salary: 3500, Department: SALES , Address: CHENNAI
ID: 104, Name: Ram , Salary: 2000, Department: HR , Address: DELHI
ID: 105, Name: Shyam , Salary: 7000, Department: ACCOUNTS , Address: GWALIOR
ID: 106, Name: Kishor, Salary: 5000, Department: SALES , Address: JHASHI
Press any key to continue . . .
Explanation
In the above program, we created four classes Employee, Department, Address, and JoinDemo. Employee class contains data members ID, Name, Salary, and DEPT_ID. Department class contains DEPT_ID and DEPT_Name and Address class contains ADD_ID and address.
Now look to the JoinDemo class, the JoinDemo class contains the Main() method. In the Main() method we created a list of employees, departments, and addresses.
var ResultQuery = (from emp in employees
join dept in departments
on emp.DEPT_ID equals dept.DEPT_ID
join add in addresses
on emp.ADD_ID equals add.ADD_ID
select new
{
ID = emp.ID ,
Name = emp.Name ,
Salary = emp.Salary ,
DeptName = dept.DEPT_Name,
address = add.address
}
).ToList();
In the above code, we joined the Employee, Department, and Address class based on DEPT_ID and ADD_ID.
Console.WriteLine("Employee Details: ");
foreach (var e in ResultQuery)
{
Console.WriteLine("\tID: " + e.ID + ", Name: " + e.Name + ", Salary: " + e.Salary + ", Department: " + e.DeptName+", Address: "+e.address);
}
The above code will print the result of join on the console screen.
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