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Rust program to implement destructive assignment with tuple

Rust | Tuple Example: Write a program to implement destructive assignment with tuple.
Submitted by Nidhi, on October 18, 2021

Problem Solution:

In this program, we will implement destructive assignments of tuple members into different variables and print them.

Program/Source Code:

The source code to implement destructive assignment with tuple is given below. The given program is compiled and executed successfully.

// Rust program to implement 
// destructive assignment 
// with tuple

fn PrintEmployee(emp:(i32,&str,u8))
{
   let (id,name,age) = emp;
   println!("Employee Information: ");
   println!("\tEmployee Id  : {}",id);
   println!("\tEmployee Name: {}",name);
   println!("\tEmployee Age : {}",age); 
}

fn main() {
   let MyTuple:(i32,&str,u8) = (101,"Dhairya Pratap",25);
   PrintEmployee(MyTuple);
}

Output:

Employee Information: 
        Employee Id  : 101
        Employee Name: Dhairya Pratap
        Employee Age : 25

Explanation:

In the above program, we created two functions PrintEmployee() and main(). The PrintEmployee() function accept tuple as a parameter and perform the destructive assignment of tuple members into a different variable.

In the main() function, we created a tuple MyTuple that contains employee information. Then we called PrintEmployee() function and printed the result.

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