Rust program to demonstrate the bitwise AND (&) operator

Here, we are going to demonstrate the bitwise AND (&) operator in Rust programming language.
Submitted by Nidhi, on September 23, 2021

Problem Solution:

Bitwise AND (&): The bitwise AND operator (&) returns a 1 in each bit position for which the corresponding bits of both operands are 1s. Here, we will perform the bitwise AND operation between two variables and print the result.

Program/Source Code:

The source code to demonstrate the bitwise AND (&) operator is given below. The given program is compiled and executed successfully.

// Rust program to demonstrate the 
// bitwise AND (&) operator

fn main() {
    let mut num1:i32 = 7;
    let mut num2:i32 = 3;
    let mut res:i32  = 0;

    res = num1 & num2;

    println!("{0} & {1} = {2}",num1,num2,res);
}

Output:

7 & 3 = 3

Explanation:

Here, we created three integer variables num1, num2, res that are initialized with 7, 3, 0 respectively. Then we performed the bitwise AND operation and printed the result.

Evolution of expression:

res = 7 & 3

0111
0011
=====
0011  that is 3

Rust Basic Programs »



Related Programs



Comments and Discussions!

Load comments ↻





Copyright © 2024 www.includehelp.com. All rights reserved.