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How to fix 'Why does the shape of a 1D array not show the number of rows as 1'?

Learn about the shape() function and why does shape() function does not given the number of rows as 1 for a 1D array?
Submitted by Pranit Sharma, on March 10, 2023

Python - numpy.shape() Method

The numpy.shape(a) is used to return the shape of a numpy array (a). By this, we mean that this function gives the dimensions of a numpy array i.e., the number of rows and columns.

It returns a tuple with two values, the first is the number of rows and the other is the number of columns.

If we apply numpy.shape() on a 1D numpy array, it will not return the number of rows as 1. This is because the concept of rows and columns applies when you have a 2D array. However, if we want the shape function to return 1 as the number of rows, we can convert it into a 2D array by giving only one row.

Let us understand with the help of an example,

Python program to demonstrate the example of numpy.shape()

# Import numpy
import numpy as np

# Creating a numpy array
arr = np.array([1,2,3,4,5])

# Display original array
print("Original array:\n",arr,"\n")

# Display shape
print("Shape:\n",arr.shape,"\n")

# Converting into 2d array and returning shape
arr = np.array([[1,2,3,4,5]])
print("Shape of array:\n",arr.shape,"\n")

Output

Example: How to fix 'Why does the shape of a 1D array not show the number of rows as 1'?