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Java StringBuilder setCharAt() method with example
StringBuilder Class setCharAt() method: Here, we are going to learn about the setCharAt() method of StringBuilder Class with its syntax and example.
Submitted by Preeti Jain, on December 22, 2019
StringBuilder Class setCharAt() method
- setCharAt() method is available in java.lang package.
- setCharAt() method is used to sets the given character at the given position and pos argument must be equal to or greater than 0 and less than the length.
- setCharAt() method is a non-static method, it is accessible with class object only and if we try to access the method with class name then we will get an error.
- setCharAt() method may throw an exception at the time of set character at the given position.
IndexOutOfBoundsException – This exception may throw when the given argument pos <0 or pos > length().
Syntax:
public void setCharAt(int pos, char c);
Parameter(s):
- int pos – represents the position where we want to set the given character.
- char c – represents the new character which we want to place.
Return value:
The return type of this method is void, it returns nothing.
Example:
// Java program to demonstrate the example
// of void setCharAt(int pos, char c)
// method of StringBuilder
public class setCharAt {
public static void main(String[] args) {
// Creating an StringBuilder object
StringBuilder st_b = new StringBuilder("Java World ");
// Display st_b
System.out.println("st_b = " + st_b);
// By using setCharAt(4,'@') method is to replace the character('')
// at index 4 in st_b with the given character('@')
st_b.setCharAt(4, '@');
// Display st_b
System.out.println("st_b.setCharAt(4,'@') = " + st_b);
}
}
Output
st_b = Java World
st_b.setCharAt(4,'@') = Java@World