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Java Collections disjoint() Method with Example
Collections Class disjoint() method: Here, we are going to learn about the disjoint() method of Collections Class with its syntax and example.
Submitted by Preeti Jain, on February 03, 2020
Collections Class disjoint() method
- disjoint() method is available in java.util package.
- disjoint() method is used to check whether the given Collection objects may contain any common elements or not.
- disjoint() method is a static method, so it is accessible with the class name and if we try to access the method with the class object then we will not get an error.
- disjoint() method may throw an exception at the time of checking no common element exists.
NullPointerException: This exception may throw when the given parameter is null exists.
Syntax:
public static boolean disjoint(Collection cl1, Collection cl2);
Parameter(s):
- Collection cl1, Collection cl2 – represent the different Collection objects.
Return value:
The return type of this method is boolean, it returns true when no common element exists in Collection object otherwise it returns false.
Example:
// Java program is to demonstrate the example
// of boolean disjoint() of Collections
import java.util.*;
public class Disjoint {
public static void main(String args[]) {
// Instantiate two LinkedList object
List < Integer > l1 = new LinkedList < Integer > ();
List < Integer > l2 = new LinkedList < Integer > ();
// By using add() method is to add
// few elements in l1
l1.add(10);
l1.add(20);
l1.add(30);
l1.add(40);
// By using add() method is to add
// few elements in l2
l2.add(60);
l2.add(70);
l2.add(80);
l2.add(90);
// Display LinkedList
System.out.println("l1: " + l1);
System.out.println("l2: " + l2);
// By using disjoint() method returns
// true when no common elements exists
// in both the collections
boolean status = Collections.disjoint(l1, l2);
System.out.println();
// Display status
System.out.println("Collections.disjoint(l1,l2): " + status);
}
}
Output
l1: [10, 20, 30, 40]
l2: [60, 70, 80, 90]
Collections.disjoint(l1,l2): true