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Java Class class getResourceAsStream() method with example
Class class getResourceAsStream() method: Here, we are going to learn about the getResourceAsStream() method of Class class with its syntax and example.
Submitted by Preeti Jain, on November 14, 2019
Class class getResourceAsStream() method
- getResourceAsStream() method is available in java.lang package.
- getResourceAsStream() method is used to get the resource as a parameter and convert the resource into InputStream.
- getResourceAsStream() method is a non-static method, it is accessible with the class object only and if we try to access the method with the class name then we will get an error.
- getResourceAsStream() method may throw an exception at the time of returning InputStream object.
NullPointerException: This exception may raise when the given resource_name is null.
Syntax:
public InputStream getResourceAsStream(String resource_name);
Parameter(s):
- String resource_name – represents the name of the resource.
Return value:
The return type of this method is InputStream, it returns the following values based on the following cases,
- It returns the InputStream, when any resource associated with the given name exists.
- It returns null, when no resource associated with the given name exists.
Example:
// Java program to demonstrate the example
// of InputStream getResourceAsStream(String resource_name)
// method of Class
import java.io.*;
import java.util.*;
public class GetResourceAsStreamOfClass {
public static String resource(String res) {
String count = "";
try {
Class cl = Class.forName("GetResourceAsStreamOfClass");
ClassLoader loader = cl.getClassLoader();
// By using getResourceAsStream() method is to take the resource
// and convert it into InputStream
InputStream is = loader.getResourceAsStream(res);
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
while ((line = br.readLine()) != null) {
count = count + 1;
}
is.close();
} catch (Exception ex) {
ex.printStackTrace();
}
return count;
}
public static void main(String[] args) throws Exception {
System.out.println(resource("Includehelp.doc"));
}
}
Output
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