Home » Java » Java find output programs

Java find output programs (Data Types) | set 1

Find the output of Java programs | Data Types | Set 1: Enhance the knowledge of Java Data Types concepts by solving and finding the output of some Java programs.
Submitted by Nidhi, on January 29, 2021

Question 1

public class MainClass {
  public static void main(String[] args) {
    int Len = 0;
    int A = 100;

    Len = sizeof(int);
    System.out.println("Len : " + Len);

    Len = sizeof(A);
    System.out.println("Len : " + Len);
  }
}

Output

MainClass.java:6: error: '.class' expected
    Len = sizeof(int);
                    ^
1 error

Explanation

The above program will generate syntax error because sizeof() operator is not exist in Java.

Question 2

public class MainClass {
  public static void main(String[] args) {
    System.out.println(Long.SIZE);
    System.out.println(Double.SIZE);
    System.out.println(Integer.SIZE);
  }
}

Output

64
64
32

Explanation

In the above program, we created a class MainClass that contains a main() method, which is the entry point for the program. Here, we used SIZE constant of Long, Double, and Integer class. The SIZE constant contains the size of specified class in bits. The size of Long is 64 it means 8 bytes.

Here, we used the println() method to print the values on the console screen.

Question 3

public class MainClass {
  public static void main(String[] args) {
    Long A = 234;
    Double PI = 3.14;

    System.out.println(A.SIZE);
    System.out.println(PI.SIZE);
  }
}

Output

MainClass.java:3: error: incompatible types: int cannot be converted to Long
    Long A = 234;
             ^
1 error

Explanation

The above program will generate syntax error because we cannot use SIZE constant with variables.

Question 4

public class Main {
  public static void main(String[] args) {
    unsigned short A = 234;
    int B = 254;
    int C = 0;

    C = A * 10 + B - A;

    System.out.println(C);
  }
}

Output

Main.java:3: error: not a statement
    unsigned short A = 234;
    ^
Main.java:3: error: ';' expected
    unsigned short A = 234;
            ^
2 errors

Explanation

The above program will generate syntax error because unsigned short is not built-in data type in java.

Question 5

public class Main {
  public static void main(String[] args) {
    short A = 234;
    int B = 254;
    int C = 0;

    C = A * 10 + B - A;

    System.out.printf("C : %d", C);
  }
}

Output

C : 2360

Explanation

In the above program, we created a class Main that contains a main() method, which is the entry point for the program. In the main() method, we created three local variables A, B, and C initialized with 234, 254, and 0 respectively.

Now evaluate the expression:

C = A*10+B-A;
C = 234*10+254-234;
C = 2340+254-234;
C = 2360

Here, we used printf() method to print the value of C in formatted manner.