What is a triangular section's moment of inertia around its base when the base is the axis of rotation?

43. What is a triangular section's moment of inertia around its base when the base is the axis of rotation?

  1. (1/12) * base * height^3
  2. (1/36) * base * height^3
  3. (1/48) * base * height^3
  4. (1/24) * base * height^3

Answer

The correct answer is: B) (1/36) * base * height^3

Explanation

This formula computes the moment of inertia of a triangular section toward its base when the base is the axis of rotation.

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